求cos1°+cos2°+cos3°+...+cos178°+cos179°的值(这里的数字都是度数比如1°)求cos1°+cos2°+cos3°+...+cos178°+cos179°的值
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/15 11:37:49
求cos1°+cos2°+cos3°+...+cos178°+cos179°的值(这里的数字都是度数比如1°)求cos1°+cos2°+cos3°+...+cos178°+cos179°的值
求cos1°+cos2°+cos3°+...+cos178°+cos179°的值(这里的数字都是度数比如1°)
求cos1°+cos2°+cos3°+...+cos178°+cos179°的值
求cos1°+cos2°+cos3°+...+cos178°+cos179°的值(这里的数字都是度数比如1°)求cos1°+cos2°+cos3°+...+cos178°+cos179°的值
cos1°+cos2°+cos3°+...+cos178°+cos179°
=(cos1°+cos179°)+(cos2°+cos178°)+……+(cos89°+cos91°)+cos90°
=(cos1°-cos1°)+(cos2°-cos2°)+……+(cos89°-cos89°)+cos90°
=cos90°
=0
2cos1度 可以首相和末尾相加就像从1加到100一样
答案为0:
cosα+cosβ=2cos[(α+β)/2] cos[(α-β)/2]
cos1°+cos179°=cos90° cos89°=0
cos2°+cos178°=cos90° cos88°=0
cos3°+cos177°=cos90° cos87°=0
..........
cos89°+cos91°=cos90° cos1°=0
cos90°=0
故cos1°+cos2°+cos3°+...+cos178°+cos179°=0
cos1°+cos2°+cos3°.+co180°=?
cos1°+cos2°+cos3°+.+cos360°
cos1°+cos2°+cos3°+...+cos179°化简
cos1°+cos2°+cos3°+.+cos359°等于多少.
求cos1°+cos2°+cos3°+...+cos178°+cos179°的值(这里的数字都是度数比如1°)求cos1°+cos2°+cos3°+...+cos178°+cos179°的值
cos1°²+cos2°²+cos3°²+cos4°²...+cos89°²=?
cos1°+cos2°+cos3°+……+cos179°+cos180°的值是(
cos1°+cos2°+cos3°+...+cos²89°过程和答案!速度啊 多谢!
cos1°+cos2°+cos3°+...+cos180°的值为?到底是0还是-1?
cos1°+cos2°+cos3°+...+cos180°的值为?
Cos1°+cos2°+cos3°+……cos89°=
cos1°+cos2°+cos3°+……cos180°=_______谢谢大家,给出过程吧~~~~
求cos1+cos2+cos3+…+cos178+cos179的值
cos1°×cos1°+cos2°×cos2°+……+cosn
(sin1°-cos1°)(sin2°-cos2°)(sin3°-cos3°)……(sin89°-cos89°)=一定要告诉我原因啊 谢谢最后得0.
cos1°的二次方+cos2°的二次方+cos3°的二次方+……cos89°的二次方=
比大小cos1,cos2,cos3,cos4
cos1 cos2 cos3 cos4 的大小关系