设实数x,y满足0

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设实数x,y满足0
设实数x,y满足0

设实数x,y满足0
x+y<1+xy
x-xy+y-1<0
x(1-y)+y-1<0
(x-1)(1-y)<0
(x-1)(y-1)>0
x>1,y>1或x<1,y<1
由0所以,0

依题意：1<1+xy<2，而001+xy-(x+y)>0，即(x-1)(y-1)>0，有：x-1>0,y-1>0或x-1<0，y-1<0
即：x>1,y>1或x<1,y<1。而01,y>1不符合有：x<1,y<1.
又由xy>0，x+y>0知，x>0，y>0。
综上有：0

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