15x561=165x51 23x352=253x32 24x462=264x42 34x473=374x43 41x154=451x14 63x396=693x3615x561=165x5123x352=253x3224x462=264x4234x473=374x4341x154=451x1463x396=693x36.以上每个等式中两边数字是分别对称的,且每个等式中组成的两位数

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15x561=165x51 23x352=253x32 24x462=264x42 34x473=374x43 41x154=451x14 63x396=693x3615x561=165x5123x352=253x3224x462=264x4234x473=374x4341x154=451x1463x396=693x36.以上每个等式中两边数字是分别对称的,且每个等式中组成的两位数

15x561=165x51 23x352=253x32 24x462=264x42 34x473=374x43 41x154=451x14 63x396=693x3615x561=165x5123x352=253x3224x462=264x4234x473=374x4341x154=451x1463x396=693x36.以上每个等式中两边数字是分别对称的,且每个等式中组成的两位数
15x561=165x51 23x352=253x32 24x462=264x42 34x473=374x43 41x154=451x14 63x396=693x36
15x561=165x51
23x352=253x32
24x462=264x42
34x473=374x43
41x154=451x14
63x396=693x36
.
以上每个等式中两边数字是分别对称的,且每个等式中组成的两位数与三位数的数字之间具有相同规律,我们称这类等式为“数字对称等式”
设这类等式左边两位是的十位数字为a,个位数字为b,其中n≤a+b≤m.
问:直接写出m、n所表示的数值.
求解~~~想了半天想不出来 ~~

15x561=165x51 23x352=253x32 24x462=264x42 34x473=374x43 41x154=451x14 63x396=693x3615x561=165x5123x352=253x3224x462=264x4234x473=374x4341x154=451x1463x396=693x36.以上每个等式中两边数字是分别对称的,且每个等式中组成的两位数
a+b不就是三位数中的那个十位数字嘛,数字最大的就是9,所以m=9;
等式左边的两位数是ab,右边的两位数是ba,如果a和b中的其中一个是零等式就是 a0+aa0=0aa+0a(例如50+550=055+05肯定是不对的),a和b如果都是零就没意思了,所以a和b最小都为1,n就等于2了

n为5,m为9

15x561=165x51 23x352=253x32 24x462=264x42 34x473=374x43 41x154=451x14 63x396=693x3615x561=165x5123x352=253x3224x462=264x4234x473=374x4341x154=451x1463x396=693x36.以上每个等式中两边数字是分别对称的,且每个等式中组成的两位数 9分之8X=6分之1x51分之16 怎么算 戴尔外星人x51怎么样 外星人x51怎么样 外星人X51有几款 观察下列等式: 12x231=132x21,13x341=143x31 23x352=253x32,34x473=374x43设这类等式左边两位数的十位数字a,个位数字为b且2小于等于a+b小于等于9,写出表示“数字对称等式”一般规律的式子(含a、b). 202平方-54平方+256x352 1/1X3+1/3X5+1/5X7.+1/49X51=?1为分子,1X3为分母 1/1X3+1/3X5+1/5x7+1/7+9+…+1/49x51=? (1/1x3)+(1/3x5)+(1/5x7)+……+(1/49x51)=如题 求改lingo程序,用sets:endsetsmin=1020*2-(48.7*(x11+x12)+52.0*(x21+x22)+61.3*(x31+x32)+72.0*(x41+x42)+48.7*(x51+x52)+52.0*(x61+x62)+64.0*(x71+x72));2*x11+3*x21+x31+0.5*x41+4*x51+2*x61+x71=0;x72>=0;@gin(x11);@gin(x21);@gin(x31);@gin(x41);@gin(x51 lingo错误提示:too many inequality or equality ralationMinY=2000*Xi1+4800*Xi2+7500*Xi3+87.5(Xi1+Xi2+Xi3);X11+X12+X13=10;X12+X13+X21+X22+X23=23;X13+X22+X23+X31+X32+X33=19;X23+X32+X33+X41+X42+X43=26;X33+X42+X43+X51+X52=20;X43+X52+X61=14;Xi1=X11+X2 ALIENWARE X51 R1 R2 有何区别 外星人的x51型号 ALWX51R-2628 怎么样. 问一个关于linux as3 的启动错误had:dma_intr:status = 0x51{driveReady seek complete error}had:dma_intr:status = 0x51{driveReady seek complete error}hda:dma_intr:error=0x40 {uncorrectable error}LBAsect = 18872745,sector = 3932232end_request:I/ 把102写成几个质数相乘的形式,正确的是( ) a.102=2x51把102写成几个质数相乘的形式,正确的是( ) a.102=2x51 b.102=1x2x3x17 c.102=2x3x17 lingo错误11 min=66*(30+h21+h22+h23)^0.51*(@sqrt((1397-x4)^2+(598-y4)^2)+66*(h21+h22+h23)^0.51*(@sqrt((x51-x4)^2+(y51-y4)^2)+66*(h22+h23)^0.51*(@sqrt((x51-x52)^2+(y51-y52)^2)+66*h23^0.51*(@sqrt((x52-x53)^2+(y52-y53)^2)+(73*30^0.712+73*h21^0.712+73*h 关于lingo的问题 运行不出结果啊model:min=x11 + x12 + x13 + x14 + x15 + x16 + x21 + x22 + x23 + x24 + x25 + x26 + x31 + x32 + x33 + x34 + x35 + x36 x41 + x42 + x43 + x44 + x45 + x46 + x51 + x52 + x51 + x54 + x55 + x56 + x61 + x62 + x63 + x6