cos(-17π/4)-sin(-17π/4)=?

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cos(-17π/4)-sin(-17π/4)=?

cos(-17π/4)-sin(-17π/4)=?
cos(-17π/4)-sin(-17π/4)=?

cos(-17π/4)-sin(-17π/4)=?
cos(-17π/4)-sin(-17π/4)
=cos(4π-17π/4)-sin(4π-17π/4)
=cos(-π/4)-sin(-π/4)
=cos(π/4)+sin(π/4)
=√2/2+√2/2
=√2
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cos(-17π/4)-sin(-17π/4)
=cos(-4π-π/4)-sin(-4π-π/4)
=cos(-π/4)-sin(-π/4)
=cos(π/4)+sin(π/4)
=√2/2+√2/2
=√2

cos(-17π/4)-sin(-17π/4)=? 求值:sin(26π/3)+cos(-17π/4)= 判断下列三角函数符号sin(-17/5派),cos(-23/4π),cos940°,cos-59/17π 怎样化简函数 cosπ/4cosπ/3-sinπ/4sinπ/3cosπ/4cosπ/3-sinπ/4sinπ/3 为什么sin(23π/5) = sin(3π/5) ,cos(17π/4) = cos(π/4)? 比较大小sin(-π/4)与sin(π/6)RT 2:cos(-23π/5)与cos(-17π/4) 比较大小sin(-π /18)与sin(-π /10)另还有cos(-23π /5)与cos(-17π /4)最好说明思路以及类似题的解法 cos(-17π/4)-sin(-17π/4)的值是什么, 用诱导法求下列三角函数值:(1)cos(-17π/4) (2)sin[(-26/3)π] sin(4分之π-β)cosβ+cos(4分之π-β)sinβ= 利用和差角公式化简 (2)sin(π/3+α)+sin(π/3-α)(2)sin(π/3+α)+sin(π/3-α)(3)cos(π/4+α)-cos(π/4-α)(4)cos(60°+α)+cos(60°-α)(5)sin(α-β)cosβ+cos(α-β)sinβ(6)cos(α+β)cosβ+sin(α+β)sinβ 由cos(a+b)=cos a cos b-sin a sin b cos(a-b)=cos a cos b+sin a sin b解题设a为锐角,证:1、2分之根3乘cos a + 2分之1乘sin a=cos(6分之π-a)2、cos a-sin a=根号2cos(4分之π+a) 用诱导公式求下列三角函数值cos(-17π/4)cos(-17π/4) sin(-2160°52′) cos(-1751°36′)sin(-26π/3)谢过了 cos^2(π/4+α)=(cos(π/4)cosα-sin(π/4)sinα)² cos^2(π/4+α)是怎么等于(cos(π/4)cosα-sin(π/4)sinα)²的? 求三角函数数值 cos(-17π/4) sin(-1574°) sin(-2160°52′) cos(-1756°36′)cos(1615°8′) sin(a-π)+5cos(2π-a)+4cos(π+a)/cos(π-a)-sin(-a) 求 化简sin(A+π/4)sin(A-π/4)/sin^4A-cos^4A 化简sin(π/4+α)cosα-sin(π/4-α)sinα