sin(x+y)+e^xy=4x,y'=

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sin(x+y)+e^xy=4x,y'=

sin(x+y)+e^xy=4x,y'=
sin(x+y)+e^xy=4x,y'=

sin(x+y)+e^xy=4x,y'=
两边对X求导,cos(x+y)*(1+y')+e^(xy)*(y+xy')=4,解得:y'=.

1L正解 分给他

是sin(x+y)+e^x * y=4x,
还是sin(x+y)+e^(xy)=4x??

两边对x求导
cos(x+y)(1+y')+e^(xy)(y+xy')=4
展开得
cos(x+y)+cos(x+y)*y'+e^(xy)*y+e^(xy)*(xy')=4
y'[cos(x+y)+xe^(xy)]=4-ye^(xy)-cos(x+y)
y'=[4-ye^(xy)-cos(x+y]/[cos(x+y)+xe^(xy)]