100+1/10(x-100)=200+1/10[x-200-100-1/10(x-100)] 好的话可以给你悬赏金的~

来源：学生作业帮助网 编辑：作业帮 时间：2024/05/09 19:26:06
100+1/10(x-100)=200+1/10[x-200-100-1/10(x-100)] 好的话可以给你悬赏金的~

100+1/10(x-100)=200+1/10[x-200-100-1/10(x-100)] 好的话可以给你悬赏金的~
100+1/10(x-100)=200+1/10[x-200-100-1/10(x-100)] 好的话可以给你悬赏金的~

100+1/10(x-100)=200+1/10[x-200-100-1/10(x-100)] 好的话可以给你悬赏金的~
设1/10(x-100)=t,则x-100=10t,x=10t+100
100+1/10(x-100)=200+1/10[x-200-100-1/10(x-100)]
100+t=200+1/10[10t-200-t]
1000+10t=2000+10t-200-t
t=800
x=10t+100=8100

（X+X)+(X-X)+(X*X)+(X/X)=100 10/150x-1=10/100x.求x 100/x+1/2=150/(x+10) x=? X+X-10+X+8=100 求x:x(10^x)=100 请帮我解一个方程 写出每一步 2[100x+10(x+1)+2x]-49=200x+10(x+1)+x 100+1/10(X-100)=200+1/10[X-(100+1/10(X-100) - 200] 100(3x-1)+10x+(2x+1)=100(2x+1)+10x+(3x+1)+99 100(3x-1)+10x+(2x+1)=100(2x+1)+10x+(3x-1)+99 100（3X-1)+10X+(2X+1)=100(2X+1)+10X+(3X-1)+99 100-2x+5x=120(x+3)×5-2x=30100-(4x+1)-(4x+1)=204x+8=6x-10 100-2x+5x=120(x+3)×5-2x=30100-(4x+1)-(4x+1)=204x+8=6x-10 x-2=(104-x)+2 6x-59=10x-75 (x+10)+(x-15)=280-x4（x-62)=x-38 60x-40=(60+20)*(x-5) 32x+32*0.5-25x+64x=24x+496-49x x+15=3*(109-x ) 5(3x-1.4)=2(6x-0.5) 3(x+0.9)=5(x-1.7) 13x-4(2x+5)=17(x-2)-4(2x-1) (13x+8)/3=5x-1x-60=2[(3561-x)+100]+1 (x+9)+12=2[(x-9)-1 100×2x+10x+3x+216=100×3x+10×2x+x 100(X - 2) + 10X + 2X = 100*2X + 10X + X - 2 - 495 1/X(X+1)+1/(X+1)(X+2)+1/(X+2)(X+3).+1/(X+99)(X+100)= 设函数f(x)=(x-1)(x-2)...(x-100)(x>100),求F'(X) f(x)=x(x-1)(x-2)…(x-99)(x-100),求f'(100)