1.0,9,26,65,124,( A.186 B.215 C.216 D.2172.19,76,28,112,36,( A.140 B.144 C.44 D.463.1,8,9,4,(),1/6 A.3 B.2 C.1 D.1/34.1,1,5,-3,10,-8,( A.-4 B.-10 C.14 D.165.某仪仗队排成方阵,第一次排列若干人,结果

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/02 08:27:58
1.0,9,26,65,124,(     A.186  B.215  C.216  D.2172.19,76,28,112,36,(     A.140  B.144  C.44   D.463.1,8,9,4,(),1/6     A.3    B.2    C.1    D.1/34.1,1,5,-3,10,-8,(     A.-4   B.-10  C.14   D.165.某仪仗队排成方阵,第一次排列若干人,结果

1.0,9,26,65,124,( A.186 B.215 C.216 D.2172.19,76,28,112,36,( A.140 B.144 C.44 D.463.1,8,9,4,(),1/6 A.3 B.2 C.1 D.1/34.1,1,5,-3,10,-8,( A.-4 B.-10 C.14 D.165.某仪仗队排成方阵,第一次排列若干人,结果
1.0,9,26,65,124,( A.186 B.215 C.216 D.2172.19,76,28,112,36,( A.140 B.144 C.44 D.463.1,8,9,4,(),1/6 A.3 B.2 C.1 D.1/34.1,1,5,-3,10,-8,( A.-4 B.-10 C.14 D.165.某仪仗队排成方阵,第一次排列若干人,结果多余100人;第二次比第一次增加3人,又少29人,仪仗队总人数为多少? A.400 B.450 C.500 D.600

1.0,9,26,65,124,( A.186 B.215 C.216 D.2172.19,76,28,112,36,( A.140 B.144 C.44 D.463.1,8,9,4,(),1/6 A.3 B.2 C.1 D.1/34.1,1,5,-3,10,-8,( A.-4 B.-10 C.14 D.165.某仪仗队排成方阵,第一次排列若干人,结果
第1题,奇数项各+1,偶数项各-1后得新数列:1,8 ,27 ,64 ,125 ,216这个分别是16的立方.因此,()=216+1=217 答案选D第2题,分组看(19,76);(28,112);(36,后1项都是前一项的4倍,于是,=144 答案选B第3题,1=1^4 8=2^3 9=3^2 4=4^1 1=5^0 1/6=6^(-1因此答案选C第4题,分奇数,偶数项来看,奇数项:1 ,5 ,10 ,偶数项:1,-3,-8,可见,奇数项的两两差分别是4,5.递增 而偶数项的两两差分别是-4,-5.递减于是,=10+6=16 答案选D第5题,设第1次方阵的边长是X,则第2次的边长是X+3,依题意得:X^2+100=(X+3)^2-29这样解得:X=20于是,仪仗队总人数是:20^2+100=500答案选C