作业帮⑴化简：[(x+1/x)ˆ6-(xˆ6=1/xˆ6)-2]/[(x+1/x)³+(x³+1/x³](请按分式的解法来解）⑵若a²-3a+1=0,则a³/(aˆ6+1)=⑶若x+y+z≠0,且x/(y+z)=y/(z+x)=z/(x+y),则x/(x+y+z)=
来源：学生作业帮助网 编辑：作业帮 时间：2024/04/29 20:49:45
![⑴化简：[(x+1/x)ˆ6-(xˆ6=1/xˆ6)-2]/[(x+1/x)³+(x³+1/x³](请按分式的解法来解）⑵若a²-3a+1=0,则a³/(aˆ6+1)=⑶若x+y+z≠0,且x/(y+z)=y/(z+x)=z/(x+y),则x/(x+y+z)=](/uploads/image/z/3936648-48-8.jpg?t=%E2%91%B4%E5%8C%96%E7%AE%80%EF%BC%9A%5B%28x%2B1%2Fx%29%26%23710%3B6-%28x%26%23710%3B6%3D1%2Fx%26%23710%3B6%29-2%5D%2F%5B%28x%2B1%2Fx%29%26sup3%3B%2B%28x%26sup3%3B%2B1%2Fx%26sup3%3B%5D%28%E8%AF%B7%E6%8C%89%E5%88%86%E5%BC%8F%E7%9A%84%E8%A7%A3%E6%B3%95%E6%9D%A5%E8%A7%A3%EF%BC%89%E2%91%B5%E8%8B%A5a%26sup2%3B-3a%2B1%3D0%2C%E5%88%99a%26sup3%3B%2F%28a%26%23710%3B6%2B1%29%3D%E2%91%B6%E8%8B%A5x%2By%2Bz%E2%89%A00%2C%E4%B8%94x%2F%28y%2Bz%29%3Dy%2F%28z%2Bx%29%3Dz%2F%28x%2By%29%2C%E5%88%99x%2F%28x%2By%2Bz%29%3D)
⑴化简：[(x+1/x)ˆ6-(xˆ6=1/xˆ6)-2]/[(x+1/x)³+(x³+1/x³](请按分式的解法来解）⑵若a²-3a+1=0,则a³/(aˆ6+1)=⑶若x+y+z≠0,且x/(y+z)=y/(z+x)=z/(x+y),则x/(x+y+z)=
⑴化简：[(x+1/x)ˆ6-(xˆ6=1/xˆ6)-2]/[(x+1/x)³+(x³+1/x³](请按分式的解法来解）
⑵若a²-3a+1=0,则a³/(aˆ6+1)=
⑶若x+y+z≠0,且x/(y+z)=y/(z+x)=z/(x+y),则x/(x+y+z)=
⑴化简：[(x+1/x)ˆ6-(xˆ6=1/xˆ6)-2]/[(x+1/x)³+(x³+1/x³](请按分式的解法来解）⑵若a²-3a+1=0,则a³/(aˆ6+1)=⑶若x+y+z≠0,且x/(y+z)=y/(z+x)=z/(x+y),则x/(x+y+z)=
第三题：
不妨设x/(y+z)=y/(z+x)=z/(x+y)=a
则x=a（y+z)
y=a(x+z)
z=a(x+y)
所以易得原式=（y+z)/2(x+y+z)