1/(m^2-m)+(m-5)/(2m^2-2) 分式计算

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1/(m^2-m)+(m-5)/(2m^2-2) 分式计算

1/(m^2-m)+(m-5)/(2m^2-2) 分式计算
1/(m^2-m)+(m-5)/(2m^2-2) 分式计算

1/(m^2-m)+(m-5)/(2m^2-2) 分式计算
1/(m^2-m)+(m-5)/(2m^2-2)
=1/[m(m-1)]+(m-5)/[2(m+1)(m-1)]
=2(m+1)/[2m(m+1)(m-1)]+m(m-5)/[2m(m+1)(m-1)]
=[2(m+1)+m(m-5)]/[2m(m+1)(m-1)]
=(m²-3m+2)/[2m(m+1)(m-1)]
=(m-1)(m-2)/[2m(m+1)(m-1)]
=(m-2)/[2m(m+1)]

=1/m(m-1)+(m-5)/2(m+1)(m-1)
=[2(m+1)+m(m+5)]/[2m(m+1)(m-1)]
=(2m+2+m^2+5m)/[2m(m+1)(m-1)]
=(m^2+7m+2)/(2m^3-2m)