an和bn是等差数列,其前N项和为sn和tn,若sn比tn等于7n+2比n+3求a5比b5则

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an和bn是等差数列,其前N项和为sn和tn,若sn比tn等于7n+2比n+3求a5比b5则

an和bn是等差数列,其前N项和为sn和tn,若sn比tn等于7n+2比n+3求a5比b5则
an和bn是等差数列,其前N项和为sn和tn,若sn比tn等于7n+2比n+3求a5比b5则

an和bn是等差数列,其前N项和为sn和tn,若sn比tn等于7n+2比n+3求a5比b5则
解,
a5/b5=65/12
解法1,a5/b5=S9/T9=65/12
解法2,Sn /Tn=7n+2/n=3
s(2n-1)/T(2n-1)=7(2n-1)+2/2n-1+3
=14n-5/2n+2
an/bn=s(2n-1)/T(2n-1)=14n-5/2n+2
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