作业帮已知α∈[5π/2,7π/2],则化简√(1+sin α)+√(1-sin α)的值为A.-2cos(α/2) B.2cos(α/2)C.-2sin(α/2) D.2sin(α/2)
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![已知α∈[5π/2,7π/2],则化简√(1+sin α)+√(1-sin α)的值为A.-2cos(α/2) B.2cos(α/2)C.-2sin(α/2) D.2sin(α/2)](/uploads/image/z/2689575-15-5.jpg?t=%E5%B7%B2%E7%9F%A5%CE%B1%E2%88%88%5B5%CF%80%2F2%2C7%CF%80%2F2%5D%2C%E5%88%99%E5%8C%96%E7%AE%80%E2%88%9A%281%2Bsin+%CE%B1%29%2B%E2%88%9A%281-sin+%CE%B1%29%E7%9A%84%E5%80%BC%E4%B8%BAA.-2cos%28%CE%B1%2F2%29+B.2cos%28%CE%B1%2F2%29C.-2sin%28%CE%B1%2F2%29+D.2sin%28%CE%B1%2F2%29)
已知α∈[5π/2,7π/2],则化简√(1+sin α)+√(1-sin α)的值为A.-2cos(α/2) B.2cos(α/2)C.-2sin(α/2) D.2sin(α/2)
已知α∈[5π/2,7π/2],则化简√(1+sin α)+√(1-sin α)的值为
A.-2cos(α/2) B.2cos(α/2)
C.-2sin(α/2) D.2sin(α/2)
已知α∈[5π/2,7π/2],则化简√(1+sin α)+√(1-sin α)的值为A.-2cos(α/2) B.2cos(α/2)C.-2sin(α/2) D.2sin(α/2)
α∈[5π/2,7π/2],
则α/2∈[5π/4,7π/4],
所以sina/2