已知x/y=2,求2x(x+y)-y(x+y)/4x²-4xy+y²的值

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已知x/y=2,求2x(x+y)-y(x+y)/4x²-4xy+y²的值
已知x/y=2,求2x(x+y)-y(x+y)/4x²-4xy+y²的值

已知x/y=2,求2x(x+y)-y(x+y)/4x²-4xy+y²的值
x/y=2,所以x=2y
2x(x+y)-y(x+y)/4x²-4xy+y²
｛2（2y）（2y+y）-y（y+2y）｝/{4*4y^2-4(2y)y+y^2}
={12y^2-3y^2}/{16y^2-8y^2+y^2}={9y^2}/{9y^2}=1
如有不明白,

x=2y
原式可化为：2y（2y+y）-y（2y+y）/（2*2y-y)(2*2y-y)=1

x =2y ，所以将这个式子带入要求的式子可得4y ·(2y +y )-y ·(2y +y )/(4y -y )^2=1。

x/y=2
x=2y
[2x(x+y)-y(x+y)=/(4x²-4xy+y² )
=(x+y)(2x-y)/(2x-y)²
=(x+y)(2x-y)
=(2y+y)/(4y-y)
=1

x/y=2,所以x=2y
2x(x+y)-y(x+y)/4x²-4xy+y²
｛2（2y）（2y+y）-y（y+2y）｝/{4*4y^2-4(2y)y+y^2}
={12y^2-3y^2}/{16y^2-8y^2+y^2}={9y^2}/{9y^2}=1

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